What are the solutions to the equation t^2-6t-1=0 ?

The solutions to the equation t^2-6t-1=0 are t=3+sqrt(10),t=3-sqrt(10)

Find the zeros of t^2-6t-1=0

The zeros of t^2-6t-1=0 are t=3+sqrt(10),t=3-sqrt(10)

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t^{2} - 6 t - 1 = 0

t = 3 + 10, t = 3 - 10

Solution steps

t^{2} - 6 t - 1 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 1) = 210

t_{1, 2} = \frac{- ( - 6 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 2 10}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 2 10}{2 \cdot 1}

t = \frac{- ( - 6 ) + 2 10}{2 \cdot 1} : 3 + 10

t = \frac{- ( - 6 ) - 2 10}{2 \cdot 1} : 3 - 10

The solutions to the quadratic equation are:

t = 3 + 10, t = 3 - 10

- 16 x^{2} + 40 x + 62 = 0

4 x^{2} + (n - 6) x - 36 = 0

u^{2} - 6 u - 7 = 0

x^{2} - x - 2 = 28

y^{2} - 14 y + 49 = 9

What are the solutions to the equation t^2-6t-1=0 ?
The solutions to the equation t^2-6t-1=0 are t=3+sqrt(10),t=3-sqrt(10)
Find the zeros of t^2-6t-1=0
The zeros of t^2-6t-1=0 are t=3+sqrt(10),t=3-sqrt(10)