What are the solutions to the equation -25x^2+144=0 ?

The solutions to the equation -25x^2+144=0 are x= 12/5 ,x=-12/5

Find the zeros of -25x^2+144=0

The zeros of -25x^2+144=0 are x= 12/5 ,x=-12/5

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- 25 x^{2} + 144 = 0

x = \frac{12}{5}, x = - \frac{12}{5}

Solution steps

- 25 x^{2} + 144 = 0

Move

144

to the right side

- 25 x^{2} = - 144

Divide both sides by

- 25

x^{2} = \frac{144}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{144}{25}, x = - \frac{144}{25}

\frac{144}{25} = \frac{12}{5}

- \frac{144}{25} = - \frac{12}{5}

x = \frac{12}{5}, x = - \frac{12}{5}

t^{2} - 6 t - 1 = 0

- 16 x^{2} + 40 x + 62 = 0

4 x^{2} + (n - 6) x - 36 = 0

u^{2} - 6 u - 7 = 0

x^{2} - x - 2 = 28

What are the solutions to the equation -25x^2+144=0 ?
The solutions to the equation -25x^2+144=0 are x= 12/5 ,x=-12/5
Find the zeros of -25x^2+144=0
The zeros of -25x^2+144=0 are x= 12/5 ,x=-12/5