What are the solutions to the equation (m^2)/4-2m+4=0 ?

The solutions to the equation (m^2)/4-2m+4=0 are m=4

Find the zeros of (m^2)/4-2m+4=0

The zeros of (m^2)/4-2m+4=0 are m=4

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\frac{m ^{2}}{4} - 2 m + 4 = 0

m = 4

Solution steps

\frac{m ^{2}}{4} - 2 m + 4 = 0

Multiply both sides by

4

m^{2} - 8 m + 16 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

m_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

m = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

m = 4

The solution to the quadratic equation is:

m = 4

64 (x - 1)^{2} = 289

\frac{9 x ^{2} - 25}{4} = 0

z^{2} + z - 3 = 0

2 (y^{2} + 3) = 11 - 13 y

6 (1 - x) + 2 = 3 x^{2} - 17

What are the solutions to the equation (m^2)/4-2m+4=0 ?
The solutions to the equation (m^2)/4-2m+4=0 are m=4
Find the zeros of (m^2)/4-2m+4=0
The zeros of (m^2)/4-2m+4=0 are m=4