What are the solutions to the equation x^2+40=-14x ?

The solutions to the equation x^2+40=-14x are x=-4,x=-10

Find the zeros of x^2+40=-14x

The zeros of x^2+40=-14x are x=-4,x=-10

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x^{2} + 40 = - 14 x

x = - 4, x = - 10

Solution steps

x^{2} + 40 = - 14 x

Move

14 x

to the left side

x^{2} + 40 + 14 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 14 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 40 = 6

x_{1, 2} = \frac{- 14 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 6}{2 \cdot 1}, x_{2} = \frac{- 14 - 6}{2 \cdot 1}

x = \frac{- 14 + 6}{2 \cdot 1} : - 4

x = \frac{- 14 - 6}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 4, x = - 10

x^{2} + 2 = 4 x

- (x - 6)^{2} + 6 = - 11

9 x^{2} - 6 x + 1 = 0

- 4 x^{2} + 7 x - 1 = 0

4 - 4 x \cdot (- 4 x + 1) = 0

What are the solutions to the equation x^2+40=-14x ?
The solutions to the equation x^2+40=-14x are x=-4,x=-10
Find the zeros of x^2+40=-14x
The zeros of x^2+40=-14x are x=-4,x=-10