What are the solutions to the equation solvefor x,y(x^2-1)=2 ?

The solutions to the equation solvefor x,y(x^2-1)=2 are x=sqrt(2/y+1),x=-sqrt(2/y+1);\quad y\ne 0

Find the zeros of solvefor x,y(x^2-1)=2

The zeros of solvefor x,y(x^2-1)=2 are x=sqrt(2/y+1),x=-sqrt(2/y+1);\quad y\ne 0

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solve for

x, y (x^{2} - 1) = 2

x = \frac{2}{y} + 1, x = - \frac{2}{y} + 1; y \neq = 0

Solution steps

y (x^{2} - 1) = 2

Divide both sides by

y; y \neq = 0

x^{2} - 1 = \frac{2}{y}; y \neq = 0

Move

1

to the right side

x^{2} = \frac{2}{y} + 1; y \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{2}{y} + 1, x = - \frac{2}{y} + 1; y \neq = 0

6 - 2 x^{2} = 6 x

x^{2} + 40 = - 14 x

x^{2} + 2 = 4 x

- (x - 6)^{2} + 6 = - 11

9 x^{2} - 6 x + 1 = 0

What are the solutions to the equation solvefor x,y(x^2-1)=2 ?
The solutions to the equation solvefor x,y(x^2-1)=2 are x=sqrt(2/y+1),x=-sqrt(2/y+1);\quad y\ne 0
Find the zeros of solvefor x,y(x^2-1)=2
The zeros of solvefor x,y(x^2-1)=2 are x=sqrt(2/y+1),x=-sqrt(2/y+1);\quad y\ne 0