What are the solutions to the equation 3q^2-108q+890=0 ?

The solutions to the equation 3q^2-108q+890=0 are q=(54+sqrt(246))/3 ,q=(54-sqrt(246))/3

Find the zeros of 3q^2-108q+890=0

The zeros of 3q^2-108q+890=0 are q=(54+sqrt(246))/3 ,q=(54-sqrt(246))/3

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3 q^{2} - 108 q + 890 = 0

q = \frac{54 + 246}{3}, q = \frac{54 - 246}{3}

Solution steps

3 q^{2} - 108 q + 890 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 108 ) \pm ( - 108 ) ^{2} - 4 \cdot 3 \cdot 890}{2 \cdot 3}

(- 108)^{2} - 4 \cdot 3 \cdot 890 = 2246

q_{1, 2} = \frac{- ( - 108 ) \pm 2 246}{2 \cdot 3}

Separate the solutions

q_{1} = \frac{- ( - 108 ) + 2 246}{2 \cdot 3}, q_{2} = \frac{- ( - 108 ) - 2 246}{2 \cdot 3}

q = \frac{- ( - 108 ) + 2 246}{2 \cdot 3} : \frac{54 + 246}{3}

q = \frac{- ( - 108 ) - 2 246}{2 \cdot 3} : \frac{54 - 246}{3}

The solutions to the quadratic equation are:

q = \frac{54 + 246}{3}, q = \frac{54 - 246}{3}

x (2 x - 7) = 15

x^{2} - 9 x = 7

7 x^{2} - 78 x = 0

x^{2} - 3 = 9

(2 a - 1) x^{2} + a x + 5 = 0

What are the solutions to the equation 3q^2-108q+890=0 ?
The solutions to the equation 3q^2-108q+890=0 are q=(54+sqrt(246))/3 ,q=(54-sqrt(246))/3
Find the zeros of 3q^2-108q+890=0
The zeros of 3q^2-108q+890=0 are q=(54+sqrt(246))/3 ,q=(54-sqrt(246))/3