What are the solutions to the equation x(2x-7)=15 ?

The solutions to the equation x(2x-7)=15 are x=5,x=-3/2

Find the zeros of x(2x-7)=15

The zeros of x(2x-7)=15 are x=5,x=-3/2

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x (2 x - 7) = 15

x = 5, x = - \frac{3}{2}

Solution steps

x (2 x - 7) = 15

Expand

x (2 x - 7) : 2 x^{2} - 7 x

2 x^{2} - 7 x = 15

Move

15

to the left side

2 x^{2} - 7 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 15) = 13

x_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 2}

x = \frac{- ( - 7 ) + 13}{2 \cdot 2} : 5

x = \frac{- ( - 7 ) - 13}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 5, x = - \frac{3}{2}

x^{2} - 9 x = 7

7 x^{2} - 78 x = 0

x^{2} - 3 = 9

(2 a - 1) x^{2} + a x + 5 = 0

(\frac{1 + x}{4})^{2} = 9

What are the solutions to the equation x(2x-7)=15 ?
The solutions to the equation x(2x-7)=15 are x=5,x=-3/2
Find the zeros of x(2x-7)=15
The zeros of x(2x-7)=15 are x=5,x=-3/2