What are the solutions to the equation 5x^2+29x+20=0 ?

The solutions to the equation 5x^2+29x+20=0 are x=-4/5 ,x=-5

Find the zeros of 5x^2+29x+20=0

The zeros of 5x^2+29x+20=0 are x=-4/5 ,x=-5

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5 x^{2} + 29 x + 20 = 0

x = - \frac{4}{5}, x = - 5

Decimal Notation

x = - 0.8, x = - 5

Solution steps

5 x^{2} + 29 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 29 \pm 2 9 ^{2} - 4 \cdot 5 \cdot 20}{2 \cdot 5}

2 9^{2} - 4 \cdot 5 \cdot 20 = 21

x_{1, 2} = \frac{- 29 \pm 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 29 + 21}{2 \cdot 5}, x_{2} = \frac{- 29 - 21}{2 \cdot 5}

x = \frac{- 29 + 21}{2 \cdot 5} : - \frac{4}{5}

x = \frac{- 29 - 21}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

x = - \frac{4}{5}, x = - 5

y = x^{2} - 9 x + 20, x

(x + 1) (8 x + 1) = 18 x

x, x^{2} - k x - 2 = 0

81 - x^{2} = 2 x^{2}

2 (x + 5)^{2} - 6 = 0

What are the solutions to the equation 5x^2+29x+20=0 ?
The solutions to the equation 5x^2+29x+20=0 are x=-4/5 ,x=-5
Find the zeros of 5x^2+29x+20=0
The zeros of 5x^2+29x+20=0 are x=-4/5 ,x=-5