What are the solutions to the equation -2x^2+5x+8=0 ?

The solutions to the equation -2x^2+5x+8=0 are x=-(-5+sqrt(89))/4 ,x=(5+sqrt(89))/4

Find the zeros of -2x^2+5x+8=0

The zeros of -2x^2+5x+8=0 are x=-(-5+sqrt(89))/4 ,x=(5+sqrt(89))/4

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- 2 x^{2} + 5 x + 8 = 0

x = - \frac{- 5 + 89}{4}, x = \frac{5 + 89}{4}

Decimal Notation

x = - 1.10849 \dots, x = 3.60849 \dots

Solution steps

- 2 x^{2} + 5 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) \cdot 8}{2 ( - 2 )}

5^{2} - 4 (- 2) \cdot 8 = 89

x_{1, 2} = \frac{- 5 \pm 89}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 5 + 89}{2 ( - 2 )}, x_{2} = \frac{- 5 - 89}{2 ( - 2 )}

x = \frac{- 5 + 89}{2 ( - 2 )} : - \frac{- 5 + 89}{4}

x = \frac{- 5 - 89}{2 ( - 2 )} : \frac{5 + 89}{4}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 89}{4}, x = \frac{5 + 89}{4}

5 x^{2} + 29 x + 20 = 0

y = x^{2} - 9 x + 20, x

(x + 1) (8 x + 1) = 18 x

x, x^{2} - k x - 2 = 0

81 - x^{2} = 2 x^{2}

What are the solutions to the equation -2x^2+5x+8=0 ?
The solutions to the equation -2x^2+5x+8=0 are x=-(-5+sqrt(89))/4 ,x=(5+sqrt(89))/4
Find the zeros of -2x^2+5x+8=0
The zeros of -2x^2+5x+8=0 are x=-(-5+sqrt(89))/4 ,x=(5+sqrt(89))/4