What are the solutions to the equation factor 2x^2=19x+33 ?

The solutions to the equation factor 2x^2=19x+33 are x=-3/2 ,x=11

Find the zeros of factor 2x^2=19x+33

The zeros of factor 2x^2=19x+33 are x=-3/2 ,x=11

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2 x^{2} = 19 x + 33

x = - \frac{3}{2}, x = 11

Decimal Notation

x = - 1.5, x = 11

Solution steps

2 x^{2} = 19 x + 33

Move

33

to the left side

2 x^{2} - 33 = 19 x

Move

19 x

to the left side

2 x^{2} - 33 - 19 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 19 x - 33 = 0

Factor

2 x^{2} - 19 x - 33 : (2 x + 3) (x - 11)

(2 x + 3) (x - 11) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or x - 11 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x - 11 = 0 : x = 11

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 11

10 x^{2} + 5 x - 2 = 0

14 x^{2} - 23 x + 15 = 12

4 t^{2} + 17 t + 18 = t^{2}

5 a^{2} - 15 a + 11 = 0

3 x^{2} - 5 = 20 - x^{2}

What are the solutions to the equation factor 2x^2=19x+33 ?
The solutions to the equation factor 2x^2=19x+33 are x=-3/2 ,x=11
Find the zeros of factor 2x^2=19x+33
The zeros of factor 2x^2=19x+33 are x=-3/2 ,x=11