What are the solutions to the equation 10x^2+5x-2=0 ?

The solutions to the equation 10x^2+5x-2=0 are x=(-5+sqrt(105))/(20),x=(-5-sqrt(105))/(20)

Find the zeros of 10x^2+5x-2=0

The zeros of 10x^2+5x-2=0 are x=(-5+sqrt(105))/(20),x=(-5-sqrt(105))/(20)

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10 x^{2} + 5 x - 2 = 0

x = \frac{- 5 + 105}{20}, x = \frac{- 5 - 105}{20}

Solution steps

10 x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 10 ( - 2 )}{2 \cdot 10}

5^{2} - 4 \cdot 10 (- 2) = 105

x_{1, 2} = \frac{- 5 \pm 105}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 5 + 105}{2 \cdot 10}, x_{2} = \frac{- 5 - 105}{2 \cdot 10}

x = \frac{- 5 + 105}{2 \cdot 10} : \frac{- 5 + 105}{20}

x = \frac{- 5 - 105}{2 \cdot 10} : \frac{- 5 - 105}{20}

The solutions to the quadratic equation are:

x = \frac{- 5 + 105}{20}, x = \frac{- 5 - 105}{20}

14 x^{2} - 23 x + 15 = 12

4 t^{2} + 17 t + 18 = t^{2}

5 a^{2} - 15 a + 11 = 0

3 x^{2} - 5 = 20 - x^{2}

\frac{y ^{2}}{2} - 3 y = 8

What are the solutions to the equation 10x^2+5x-2=0 ?
The solutions to the equation 10x^2+5x-2=0 are x=(-5+sqrt(105))/(20),x=(-5-sqrt(105))/(20)
Find the zeros of 10x^2+5x-2=0
The zeros of 10x^2+5x-2=0 are x=(-5+sqrt(105))/(20),x=(-5-sqrt(105))/(20)