What are the solutions to the equation 14x^2-23x+15=12 ?

The solutions to the equation 14x^2-23x+15=12 are x= 3/2 ,x= 1/7

Find the zeros of 14x^2-23x+15=12

The zeros of 14x^2-23x+15=12 are x= 3/2 ,x= 1/7

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14 x^{2} - 23 x + 15 = 12

x = \frac{3}{2}, x = \frac{1}{7}

Solution steps

14 x^{2} - 23 x + 15 = 12

Move

12

to the left side

14 x^{2} - 23 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 14 \cdot 3}{2 \cdot 14}

(- 23)^{2} - 4 \cdot 14 \cdot 3 = 19

x_{1, 2} = \frac{- ( - 23 ) \pm 19}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 19}{2 \cdot 14}, x_{2} = \frac{- ( - 23 ) - 19}{2 \cdot 14}

x = \frac{- ( - 23 ) + 19}{2 \cdot 14} : \frac{3}{2}

x = \frac{- ( - 23 ) - 19}{2 \cdot 14} : \frac{1}{7}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{1}{7}

4 t^{2} + 17 t + 18 = t^{2}

5 a^{2} - 15 a + 11 = 0

3 x^{2} - 5 = 20 - x^{2}

\frac{y ^{2}}{2} - 3 y = 8

2 p^{2} + 13 p + 17 = 0

What are the solutions to the equation 14x^2-23x+15=12 ?
The solutions to the equation 14x^2-23x+15=12 are x= 3/2 ,x= 1/7
Find the zeros of 14x^2-23x+15=12
The zeros of 14x^2-23x+15=12 are x= 3/2 ,x= 1/7