What are the solutions to the equation (y^2)/2-3y=8 ?

The solutions to the equation (y^2)/2-3y=8 are y=8,y=-2

Find the zeros of (y^2)/2-3y=8

The zeros of (y^2)/2-3y=8 are y=8,y=-2

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\frac{y ^{2}}{2} - 3 y = 8

y = 8, y = - 2

Solution steps

\frac{y ^{2}}{2} - 3 y = 8

Multiply both sides by

2

y^{2} - 6 y = 16

Move

16

to the left side

y^{2} - 6 y - 16 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 16) = 10

y_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 10}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 10}{2 \cdot 1}

y = \frac{- ( - 6 ) + 10}{2 \cdot 1} : 8

y = \frac{- ( - 6 ) - 10}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

y = 8, y = - 2

2 p^{2} + 13 p + 17 = 0

x^{2} + 16 x = - 59

3 (4 b^{2} - 7) = - 2 b - 8

4 x^{2} + 20 x

x - 7 = (x - 1)^{2}

What are the solutions to the equation (y^2)/2-3y=8 ?
The solutions to the equation (y^2)/2-3y=8 are y=8,y=-2
Find the zeros of (y^2)/2-3y=8
The zeros of (y^2)/2-3y=8 are y=8,y=-2