What are the solutions to the equation 2m^2-8m=0 ?

The solutions to the equation 2m^2-8m=0 are m=4,m=0

Find the zeros of 2m^2-8m=0

The zeros of 2m^2-8m=0 are m=4,m=0

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2 m^{2} - 8 m = 0

m = 4, m = 0

Solution steps

2 m^{2} - 8 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 0 = 8

m_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 2}, m_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 2}

m = \frac{- ( - 8 ) + 8}{2 \cdot 2} : 4

m = \frac{- ( - 8 ) - 8}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

m = 4, m = 0

4 - 2 x + 3 x^{2} = 0

x, y = \frac{x ^{2}}{4}

(x - 4)^{2} + 3 (x + 1) (x - 2) = 8

x, f (x + 2) = x^{2} - x

r^{2} - 144 = 0

What are the solutions to the equation 2m^2-8m=0 ?
The solutions to the equation 2m^2-8m=0 are m=4,m=0
Find the zeros of 2m^2-8m=0
The zeros of 2m^2-8m=0 are m=4,m=0