What are the solutions to the equation 15x^2=540 ?

The solutions to the equation 15x^2=540 are x=6,x=-6

Find the zeros of 15x^2=540

The zeros of 15x^2=540 are x=6,x=-6

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15 x^{2} = 540

x = 6, x = - 6

Solution steps

15 x^{2} = 540

Divide both sides by

15

x^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 36, x = - 36

36 = 6

- 36 = - 6

x = 6, x = - 6

9 x^{2} + 18 x - 17 = 0

\frac{17}{10} x^{2} + 3 x + 5 = 0

6 w^{2} - 12 w = 0

5 t^{2} + 13 t - 6 = 0

x^{2} = - 3 + 4 x

What are the solutions to the equation 15x^2=540 ?
The solutions to the equation 15x^2=540 are x=6,x=-6
Find the zeros of 15x^2=540
The zeros of 15x^2=540 are x=6,x=-6