What are the solutions to the equation 5t^2+13t-6=0 ?

The solutions to the equation 5t^2+13t-6=0 are t= 2/5 ,t=-3

Find the zeros of 5t^2+13t-6=0

The zeros of 5t^2+13t-6=0 are t= 2/5 ,t=-3

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5 t^{2} + 13 t - 6 = 0

t = \frac{2}{5}, t = - 3

Solution steps

5 t^{2} + 13 t - 6 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

1 3^{2} - 4 \cdot 5 (- 6) = 17

t_{1, 2} = \frac{- 13 \pm 17}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- 13 + 17}{2 \cdot 5}, t_{2} = \frac{- 13 - 17}{2 \cdot 5}

t = \frac{- 13 + 17}{2 \cdot 5} : \frac{2}{5}

t = \frac{- 13 - 17}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

t = \frac{2}{5}, t = - 3

x^{2} = - 3 + 4 x

4 n^{2} + 6 n - 9 = 0

x^{2} - 2 x = - 26

x^{2} + (- 3) x + 2 = 0

5 t^{2} - 5 t - 30 = 0

What are the solutions to the equation 5t^2+13t-6=0 ?
The solutions to the equation 5t^2+13t-6=0 are t= 2/5 ,t=-3
Find the zeros of 5t^2+13t-6=0
The zeros of 5t^2+13t-6=0 are t= 2/5 ,t=-3