What are the solutions to the equation 9x^2+18x-17=0 ?

The solutions to the equation 9x^2+18x-17=0 are x=(-3+sqrt(26))/3 ,x=-(3+sqrt(26))/3

Find the zeros of 9x^2+18x-17=0

The zeros of 9x^2+18x-17=0 are x=(-3+sqrt(26))/3 ,x=-(3+sqrt(26))/3

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9 x^{2} + 18 x - 17 = 0

x = \frac{- 3 + 26}{3}, x = - \frac{3 + 26}{3}

Solution steps

9 x^{2} + 18 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 ( - 17 )}{2 \cdot 9}

1 8^{2} - 4 \cdot 9 (- 17) = 626

x_{1, 2} = \frac{- 18 \pm 6 26}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 18 + 6 26}{2 \cdot 9}, x_{2} = \frac{- 18 - 6 26}{2 \cdot 9}

x = \frac{- 18 + 6 26}{2 \cdot 9} : \frac{- 3 + 26}{3}

x = \frac{- 18 - 6 26}{2 \cdot 9} : - \frac{3 + 26}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 26}{3}, x = - \frac{3 + 26}{3}

\frac{17}{10} x^{2} + 3 x + 5 = 0

6 w^{2} - 12 w = 0

5 t^{2} + 13 t - 6 = 0

x^{2} = - 3 + 4 x

4 n^{2} + 6 n - 9 = 0

What are the solutions to the equation 9x^2+18x-17=0 ?
The solutions to the equation 9x^2+18x-17=0 are x=(-3+sqrt(26))/3 ,x=-(3+sqrt(26))/3
Find the zeros of 9x^2+18x-17=0
The zeros of 9x^2+18x-17=0 are x=(-3+sqrt(26))/3 ,x=-(3+sqrt(26))/3