What are the solutions to the equation y^2-12y=-25 ?

The solutions to the equation y^2-12y=-25 are y=6+sqrt(11),y=6-sqrt(11)

Find the zeros of y^2-12y=-25

The zeros of y^2-12y=-25 are y=6+sqrt(11),y=6-sqrt(11)

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y^{2} - 12 y = - 25

y = 6 + 11, y = 6 - 11

Decimal Notation

y = 9.31662 \dots, y = 2.68337 \dots

Solution steps

y^{2} - 12 y = - 25

Move

25

to the left side

y^{2} - 12 y + 25 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 25 = 211

y_{1, 2} = \frac{- ( - 12 ) \pm 2 11}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 12 ) + 2 11}{2 \cdot 1}, y_{2} = \frac{- ( - 12 ) - 2 11}{2 \cdot 1}

y = \frac{- ( - 12 ) + 2 11}{2 \cdot 1} : 6 + 11

y = \frac{- ( - 12 ) - 2 11}{2 \cdot 1} : 6 - 11

The solutions to the quadratic equation are:

y = 6 + 11, y = 6 - 11

x^{2} - 35 x = 60

3 s^{2} - 22 s = 16

3 x^{2} - 3 x = x - 1

y, y^{2} = 15 x^{3} + 2 x y

(1 - x) (- 3 - x) - 2 = 0

What are the solutions to the equation y^2-12y=-25 ?
The solutions to the equation y^2-12y=-25 are y=6+sqrt(11),y=6-sqrt(11)
Find the zeros of y^2-12y=-25
The zeros of y^2-12y=-25 are y=6+sqrt(11),y=6-sqrt(11)