What are the solutions to the equation 3s^2-22s=16 ?

The solutions to the equation 3s^2-22s=16 are s=8,s=-2/3

Find the zeros of 3s^2-22s=16

The zeros of 3s^2-22s=16 are s=8,s=-2/3

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3 s^{2} - 22 s = 16

s = 8, s = - \frac{2}{3}

Decimal Notation

s = 8, s = - 0.66666 \dots

Solution steps

3 s^{2} - 22 s = 16

Move

16

to the left side

3 s^{2} - 22 s - 16 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

(- 22)^{2} - 4 \cdot 3 (- 16) = 26

s_{1, 2} = \frac{- ( - 22 ) \pm 26}{2 \cdot 3}

Separate the solutions

s_{1} = \frac{- ( - 22 ) + 26}{2 \cdot 3}, s_{2} = \frac{- ( - 22 ) - 26}{2 \cdot 3}

s = \frac{- ( - 22 ) + 26}{2 \cdot 3} : 8

s = \frac{- ( - 22 ) - 26}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

s = 8, s = - \frac{2}{3}

3 x^{2} - 3 x = x - 1

y, y^{2} = 15 x^{3} + 2 x y

(1 - x) (- 3 - x) - 2 = 0

- 2 x^{2} - 16 x - 35 = 0

(2 t - 1) t = 66

What are the solutions to the equation 3s^2-22s=16 ?
The solutions to the equation 3s^2-22s=16 are s=8,s=-2/3
Find the zeros of 3s^2-22s=16
The zeros of 3s^2-22s=16 are s=8,s=-2/3