What are the solutions to the equation x^2-35x=60 ?

The solutions to the equation x^2-35x=60 are x=(35+sqrt(1465))/2 ,x=(35-sqrt(1465))/2

Find the zeros of x^2-35x=60

The zeros of x^2-35x=60 are x=(35+sqrt(1465))/2 ,x=(35-sqrt(1465))/2

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x^{2} - 35 x = 60

x = \frac{35 + 1465}{2}, x = \frac{35 - 1465}{2}

Decimal Notation

x = 36.63765 \dots, x = - 1.63765 \dots

Solution steps

x^{2} - 35 x = 60

Move

60

to the left side

x^{2} - 35 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 35 ) \pm ( - 35 ) ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

(- 35)^{2} - 4 \cdot 1 \cdot (- 60) = 1465

x_{1, 2} = \frac{- ( - 35 ) \pm 1465}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 35 ) + 1465}{2 \cdot 1}, x_{2} = \frac{- ( - 35 ) - 1465}{2 \cdot 1}

x = \frac{- ( - 35 ) + 1465}{2 \cdot 1} : \frac{35 + 1465}{2}

x = \frac{- ( - 35 ) - 1465}{2 \cdot 1} : \frac{35 - 1465}{2}

The solutions to the quadratic equation are:

x = \frac{35 + 1465}{2}, x = \frac{35 - 1465}{2}

3 s^{2} - 22 s = 16

3 x^{2} - 3 x = x - 1

y, y^{2} = 15 x^{3} + 2 x y

(1 - x) (- 3 - x) - 2 = 0

- 2 x^{2} - 16 x - 35 = 0

What are the solutions to the equation x^2-35x=60 ?
The solutions to the equation x^2-35x=60 are x=(35+sqrt(1465))/2 ,x=(35-sqrt(1465))/2
Find the zeros of x^2-35x=60
The zeros of x^2-35x=60 are x=(35+sqrt(1465))/2 ,x=(35-sqrt(1465))/2