What are the solutions to the equation -2x^2-16x-35=0 ?

The solutions to the equation -2x^2-16x-35=0 are x=-4-isqrt(3/2),x=-4+isqrt(3/2)

Find the zeros of -2x^2-16x-35=0

The zeros of -2x^2-16x-35=0 are x=-4-isqrt(3/2),x=-4+isqrt(3/2)

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- 2 x^{2} - 16 x - 35 = 0

x = - 4 - i \frac{3}{2}, x = - 4 + i \frac{3}{2}

Solution steps

- 2 x^{2} - 16 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 2 ) ( - 35 )}{2 ( - 2 )}

Simplify

(- 16)^{2} - 4 (- 2) (- 35) : 26 i

x_{1, 2} = \frac{- ( - 16 ) \pm 2 6 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 6 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 16 ) - 2 6 i}{2 ( - 2 )}

x = \frac{- ( - 16 ) + 2 6 i}{2 ( - 2 )} : - 4 - i \frac{3}{2}

x = \frac{- ( - 16 ) - 2 6 i}{2 ( - 2 )} : - 4 + i \frac{3}{2}

The solutions to the quadratic equation are:

x = - 4 - i \frac{3}{2}, x = - 4 + i \frac{3}{2}

(2 t - 1) t = 66

(x + 2)^{2} = 2 (x + 6)

t^{2} - 2 t + 0.4082 = 0

\frac{5}{7} x^{2} - x = \frac{2}{7}

3 r^{2} - 8 r + 4 = 0

What are the solutions to the equation -2x^2-16x-35=0 ?
The solutions to the equation -2x^2-16x-35=0 are x=-4-isqrt(3/2),x=-4+isqrt(3/2)
Find the zeros of -2x^2-16x-35=0
The zeros of -2x^2-16x-35=0 are x=-4-isqrt(3/2),x=-4+isqrt(3/2)