What are the solutions to the equation (2t-1)t=66 ?

The solutions to the equation (2t-1)t=66 are t=6,t=-11/2

Find the zeros of (2t-1)t=66

The zeros of (2t-1)t=66 are t=6,t=-11/2

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(2 t - 1) t = 66

t = 6, t = - \frac{11}{2}

Decimal Notation

t = 6, t = - 5.5

Solution steps

(2 t - 1) t = 66

Expand

(2 t - 1) t : 2 t^{2} - t

2 t^{2} - t = 66

Move

66

to the left side

2 t^{2} - t - 66 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 66 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 66) = 23

t_{1, 2} = \frac{- ( - 1 ) \pm 23}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 1 ) + 23}{2 \cdot 2}, t_{2} = \frac{- ( - 1 ) - 23}{2 \cdot 2}

t = \frac{- ( - 1 ) + 23}{2 \cdot 2} : 6

t = \frac{- ( - 1 ) - 23}{2 \cdot 2} : - \frac{11}{2}

The solutions to the quadratic equation are:

t = 6, t = - \frac{11}{2}

(x + 2)^{2} = 2 (x + 6)

t^{2} - 2 t + 0.4082 = 0

\frac{5}{7} x^{2} - x = \frac{2}{7}

3 r^{2} - 8 r + 4 = 0

4 x^{2} = 60 x

What are the solutions to the equation (2t-1)t=66 ?
The solutions to the equation (2t-1)t=66 are t=6,t=-11/2
Find the zeros of (2t-1)t=66
The zeros of (2t-1)t=66 are t=6,t=-11/2