What are the solutions to the equation 3x^2+5(2x+1)=0 ?

The solutions to the equation 3x^2+5(2x+1)=0 are x=(-5+sqrt(10))/3 ,x=-(5+sqrt(10))/3

Find the zeros of 3x^2+5(2x+1)=0

The zeros of 3x^2+5(2x+1)=0 are x=(-5+sqrt(10))/3 ,x=-(5+sqrt(10))/3

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3 x^{2} + 5 (2 x + 1) = 0

x = \frac{- 5 + 10}{3}, x = - \frac{5 + 10}{3}

Decimal Notation

x = - 0.61257 \dots, x = - 2.72075 \dots

Solution steps

3 x^{2} + 5 (2 x + 1) = 0

Expand

3 x^{2} + 5 (2 x + 1) : 3 x^{2} + 10 x + 5

3 x^{2} + 10 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 \cdot 5 = 210

x_{1, 2} = \frac{- 10 \pm 2 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 2 10}{2 \cdot 3}, x_{2} = \frac{- 10 - 2 10}{2 \cdot 3}

x = \frac{- 10 + 2 10}{2 \cdot 3} : \frac{- 5 + 10}{3}

x = \frac{- 10 - 2 10}{2 \cdot 3} : - \frac{5 + 10}{3}

The solutions to the quadratic equation are:

x = \frac{- 5 + 10}{3}, x = - \frac{5 + 10}{3}

- 2 (x - 6)^{2} + 7 = - 23

(\frac{2}{3}) x^{2} + 5 x - 9 = 0

r^{2} + 10 r - 18 = 61

h^{2} - 4 h - 32 = 0

G (x) = x^{2} + 2

What are the solutions to the equation 3x^2+5(2x+1)=0 ?
The solutions to the equation 3x^2+5(2x+1)=0 are x=(-5+sqrt(10))/3 ,x=-(5+sqrt(10))/3
Find the zeros of 3x^2+5(2x+1)=0
The zeros of 3x^2+5(2x+1)=0 are x=(-5+sqrt(10))/3 ,x=-(5+sqrt(10))/3