What are the solutions to the equation -2(x-6)^2+7=-23 ?

The solutions to the equation -2(x-6)^2+7=-23 are x=sqrt(15)+6,x=-sqrt(15)+6

Find the zeros of -2(x-6)^2+7=-23

The zeros of -2(x-6)^2+7=-23 are x=sqrt(15)+6,x=-sqrt(15)+6

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- 2 (x - 6)^{2} + 7 = - 23

x = 15 + 6, x = - 15 + 6

Decimal Notation

x = 9.87298 \dots, x = 2.12701 \dots

Solution steps

- 2 (x - 6)^{2} + 7 = - 23

Move

7

to the right side

- 2 (x - 6)^{2} = - 30

Divide both sides by

- 2

(x - 6)^{2} = 15

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 6 = 15 : x = 15 + 6

Solve

x - 6 = - 15 : x = - 15 + 6

The solutions to the quadratic equation are:

x = 15 + 6, x = - 15 + 6

(\frac{2}{3}) x^{2} + 5 x - 9 = 0

r^{2} + 10 r - 18 = 61

h^{2} - 4 h - 32 = 0

G (x) = x^{2} + 2

y^{2} - 4 y + 9 = 0

What are the solutions to the equation -2(x-6)^2+7=-23 ?
The solutions to the equation -2(x-6)^2+7=-23 are x=sqrt(15)+6,x=-sqrt(15)+6
Find the zeros of -2(x-6)^2+7=-23
The zeros of -2(x-6)^2+7=-23 are x=sqrt(15)+6,x=-sqrt(15)+6