What are the solutions to the equation x^2+9x=27 ?

The solutions to the equation x^2+9x=27 are x=(-9+3sqrt(21))/2 ,x=(-9-3sqrt(21))/2

Find the zeros of x^2+9x=27

The zeros of x^2+9x=27 are x=(-9+3sqrt(21))/2 ,x=(-9-3sqrt(21))/2

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x^{2} + 9 x = 27

x = \frac{- 9 + 3 21}{2}, x = \frac{- 9 - 3 21}{2}

Decimal Notation

x = 2.37386 \dots, x = - 11.37386 \dots

Solution steps

x^{2} + 9 x = 27

Move

27

to the left side

x^{2} + 9 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 27) = 321

x_{1, 2} = \frac{- 9 \pm 3 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 3 21}{2 \cdot 1}, x_{2} = \frac{- 9 - 3 21}{2 \cdot 1}

x = \frac{- 9 + 3 21}{2 \cdot 1} : \frac{- 9 + 3 21}{2}

x = \frac{- 9 - 3 21}{2 \cdot 1} : \frac{- 9 - 3 21}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 3 21}{2}, x = \frac{- 9 - 3 21}{2}

2 x^{2} - 10 x + 9 = 0

100 x^{2} = 1

3 x^{2} + 9 x - 26 = 4 x^{2} - x - 1

x, 3 x^{2} - m x + 15 = 0

2 x (x - 4) + 1 = 1 - 2 x

What are the solutions to the equation x^2+9x=27 ?
The solutions to the equation x^2+9x=27 are x=(-9+3sqrt(21))/2 ,x=(-9-3sqrt(21))/2
Find the zeros of x^2+9x=27
The zeros of x^2+9x=27 are x=(-9+3sqrt(21))/2 ,x=(-9-3sqrt(21))/2