What are the solutions to the equation 3x^2+9x-26=4x^2-x-1 ?

The solutions to the equation 3x^2+9x-26=4x^2-x-1 are x=5

Find the zeros of 3x^2+9x-26=4x^2-x-1

The zeros of 3x^2+9x-26=4x^2-x-1 are x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 9 x - 26 = 4 x^{2} - x - 1

x = 5

Solution steps

3 x^{2} + 9 x - 26 = 4 x^{2} - x - 1

Move

1

to the left side

3 x^{2} + 9 x - 25 = 4 x^{2} - x

Move

x

to the left side

3 x^{2} + 10 x - 25 = 4 x^{2}

Move

4 x^{2}

to the left side

- x^{2} + 10 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 25 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 25) = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 ( - 1 )}

x = \frac{- 10}{2 ( - 1 )}

\frac{- 10}{2 ( - 1 )} = 5

x = 5

The solution to the quadratic equation is:

x = 5

x, 3 x^{2} - m x + 15 = 0

2 x (x - 4) + 1 = 1 - 2 x

(5 x - 1)^{2} = 3

3 x^{2} + (3 + 1) x - 2 = 0

4 x^{2} - 7 x + 15 = 0

What are the solutions to the equation 3x^2+9x-26=4x^2-x-1 ?
The solutions to the equation 3x^2+9x-26=4x^2-x-1 are x=5
Find the zeros of 3x^2+9x-26=4x^2-x-1
The zeros of 3x^2+9x-26=4x^2-x-1 are x=5