What are the solutions to the equation 2x(x-4)+1=1-2x ?

The solutions to the equation 2x(x-4)+1=1-2x are x=3,x=0

Find the zeros of 2x(x-4)+1=1-2x

The zeros of 2x(x-4)+1=1-2x are x=3,x=0

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2 x (x - 4) + 1 = 1 - 2 x

x = 3, x = 0

Solution steps

2 x (x - 4) + 1 = 1 - 2 x

Expand

2 x (x - 4) + 1 : 2 x^{2} - 8 x + 1

2 x^{2} - 8 x + 1 = 1 - 2 x

Move

2 x

to the left side

2 x^{2} - 6 x + 1 = 1

Move

1

to the left side

2 x^{2} - 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 2}

x = \frac{- ( - 6 ) + 6}{2 \cdot 2} : 3

x = \frac{- ( - 6 ) - 6}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

(5 x - 1)^{2} = 3

3 x^{2} + (3 + 1) x - 2 = 0

4 x^{2} - 7 x + 15 = 0

(2 x - 1) (2 x + 1) = 0

n^{2} + 7 n = 8

What are the solutions to the equation 2x(x-4)+1=1-2x ?
The solutions to the equation 2x(x-4)+1=1-2x are x=3,x=0
Find the zeros of 2x(x-4)+1=1-2x
The zeros of 2x(x-4)+1=1-2x are x=3,x=0