What are the solutions to the equation 4x^2-7x+15=0 ?

The solutions to the equation 4x^2-7x+15=0 are x= 7/8+i(sqrt(191))/8 ,x= 7/8-i(sqrt(191))/8

Find the zeros of 4x^2-7x+15=0

The zeros of 4x^2-7x+15=0 are x= 7/8+i(sqrt(191))/8 ,x= 7/8-i(sqrt(191))/8

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4 x^{2} - 7 x + 15 = 0

x = \frac{7}{8} + i \frac{191}{8}, x = \frac{7}{8} - i \frac{191}{8}

Solution steps

4 x^{2} - 7 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 \cdot 15}{2 \cdot 4}

Simplify

(- 7)^{2} - 4 \cdot 4 \cdot 15 : 191 i

x_{1, 2} = \frac{- ( - 7 ) \pm 191 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 191 i}{2 \cdot 4}, x_{2} = \frac{- ( - 7 ) - 191 i}{2 \cdot 4}

x = \frac{- ( - 7 ) + 191 i}{2 \cdot 4} : \frac{7}{8} + i \frac{191}{8}

x = \frac{- ( - 7 ) - 191 i}{2 \cdot 4} : \frac{7}{8} - i \frac{191}{8}

The solutions to the quadratic equation are:

x = \frac{7}{8} + i \frac{191}{8}, x = \frac{7}{8} - i \frac{191}{8}

(2 x - 1) (2 x + 1) = 0

n^{2} + 7 n = 8

3 x + 2 x^{2} = 5 x^{2} - 6

x^{2} - 3 a x + a^{2} = 0

15 + (x - 4)^{2} = 7

What are the solutions to the equation 4x^2-7x+15=0 ?
The solutions to the equation 4x^2-7x+15=0 are x= 7/8+i(sqrt(191))/8 ,x= 7/8-i(sqrt(191))/8
Find the zeros of 4x^2-7x+15=0
The zeros of 4x^2-7x+15=0 are x= 7/8+i(sqrt(191))/8 ,x= 7/8-i(sqrt(191))/8