What are the solutions to the equation (2x-1)(2x+1)=0 ?

The solutions to the equation (2x-1)(2x+1)=0 are x= 1/2 ,x=-1/2

Find the zeros of (2x-1)(2x+1)=0

The zeros of (2x-1)(2x+1)=0 are x= 1/2 ,x=-1/2

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(2 x - 1) (2 x + 1) = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.5, x = - 0.5

Solution steps

(2 x - 1) (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or 2 x + 1 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{1}{2}

n^{2} + 7 n = 8

3 x + 2 x^{2} = 5 x^{2} - 6

x^{2} - 3 a x + a^{2} = 0

15 + (x - 4)^{2} = 7

3 (x^{2} - 3) = 35 x + 19

What are the solutions to the equation (2x-1)(2x+1)=0 ?
The solutions to the equation (2x-1)(2x+1)=0 are x= 1/2 ,x=-1/2
Find the zeros of (2x-1)(2x+1)=0
The zeros of (2x-1)(2x+1)=0 are x= 1/2 ,x=-1/2