What are the solutions to the equation m^2+16m+73=0 ?

The solutions to the equation m^2+16m+73=0 are m=-8+3i,m=-8-3i

Find the zeros of m^2+16m+73=0

The zeros of m^2+16m+73=0 are m=-8+3i,m=-8-3i

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m^{2} + 16 m + 73 = 0

m = - 8 + 3 i, m = - 8 - 3 i

Solution steps

m^{2} + 16 m + 73 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 73}{2 \cdot 1}

Simplify

1 6^{2} - 4 \cdot 1 \cdot 73 : 6 i

m_{1, 2} = \frac{- 16 \pm 6 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 16 + 6 i}{2 \cdot 1}, m_{2} = \frac{- 16 - 6 i}{2 \cdot 1}

m = \frac{- 16 + 6 i}{2 \cdot 1} : - 8 + 3 i

m = \frac{- 16 - 6 i}{2 \cdot 1} : - 8 - 3 i

The solutions to the quadratic equation are:

m = - 8 + 3 i, m = - 8 - 3 i

v^{2} + 7 v + 12 = 0

4 t^{2} + 19 t - 30 = 0

9 x^{2} - 12 x - 12 = 0

x, x (x - 4) = 140

x^{2} = 10 x - 50

What are the solutions to the equation m^2+16m+73=0 ?
The solutions to the equation m^2+16m+73=0 are m=-8+3i,m=-8-3i
Find the zeros of m^2+16m+73=0
The zeros of m^2+16m+73=0 are m=-8+3i,m=-8-3i