What are the solutions to the equation x^2=10x-50 ?

The solutions to the equation x^2=10x-50 are x=5+5i,x=5-5i

Find the zeros of x^2=10x-50

The zeros of x^2=10x-50 are x=5+5i,x=5-5i

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x^{2} = 10 x - 50

x = 5 + 5 i, x = 5 - 5 i

Solution steps

x^{2} = 10 x - 50

Move

50

to the left side

x^{2} + 50 = 10 x

Move

10 x

to the left side

x^{2} + 50 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 10 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 50 : 10 i

x_{1, 2} = \frac{- ( - 10 ) \pm 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 10 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 10 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 10 i}{2 \cdot 1} : 5 + 5 i

x = \frac{- ( - 10 ) - 10 i}{2 \cdot 1} : 5 - 5 i

The solutions to the quadratic equation are:

x = 5 + 5 i, x = 5 - 5 i

x^{2} - 14 x + 20 = - 4

6 y^{2} - 7 y + 2 = 0

x - (x - 7)^{2} = 1 + x - 6 x^{2}

3 + 2 x - x^{2}

x, 3 x^{2} + k x + 12 = 0

What are the solutions to the equation x^2=10x-50 ?
The solutions to the equation x^2=10x-50 are x=5+5i,x=5-5i
Find the zeros of x^2=10x-50
The zeros of x^2=10x-50 are x=5+5i,x=5-5i