What are the solutions to the equation v^2+7v+12=0 ?

The solutions to the equation v^2+7v+12=0 are v=-3,v=-4

Find the zeros of v^2+7v+12=0

The zeros of v^2+7v+12=0 are v=-3,v=-4

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v^{2} + 7 v + 12 = 0

v = - 3, v = - 4

Solution steps

v^{2} + 7 v + 12 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

v_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 7 + 1}{2 \cdot 1}, v_{2} = \frac{- 7 - 1}{2 \cdot 1}

v = \frac{- 7 + 1}{2 \cdot 1} : - 3

v = \frac{- 7 - 1}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

v = - 3, v = - 4

4 t^{2} + 19 t - 30 = 0

9 x^{2} - 12 x - 12 = 0

x, x (x - 4) = 140

x^{2} = 10 x - 50

x^{2} - 14 x + 20 = - 4

What are the solutions to the equation v^2+7v+12=0 ?
The solutions to the equation v^2+7v+12=0 are v=-3,v=-4
Find the zeros of v^2+7v+12=0
The zeros of v^2+7v+12=0 are v=-3,v=-4