What are the solutions to the equation 5a^2-3a+6=2 ?

The solutions to the equation 5a^2-3a+6=2 are a= 3/10+i(sqrt(71))/(10),a= 3/10-i(sqrt(71))/(10)

Find the zeros of 5a^2-3a+6=2

The zeros of 5a^2-3a+6=2 are a= 3/10+i(sqrt(71))/(10),a= 3/10-i(sqrt(71))/(10)

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5 a^{2} - 3 a + 6 = 2

a = \frac{3}{10} + i \frac{71}{10}, a = \frac{3}{10} - i \frac{71}{10}

Solution steps

5 a^{2} - 3 a + 6 = 2

Move

2

to the left side

5 a^{2} - 3 a + 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

Simplify

(- 3)^{2} - 4 \cdot 5 \cdot 4 : 71 i

a_{1, 2} = \frac{- ( - 3 ) \pm 71 i}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- ( - 3 ) + 71 i}{2 \cdot 5}, a_{2} = \frac{- ( - 3 ) - 71 i}{2 \cdot 5}

a = \frac{- ( - 3 ) + 71 i}{2 \cdot 5} : \frac{3}{10} + i \frac{71}{10}

a = \frac{- ( - 3 ) - 71 i}{2 \cdot 5} : \frac{3}{10} - i \frac{71}{10}

The solutions to the quadratic equation are:

a = \frac{3}{10} + i \frac{71}{10}, a = \frac{3}{10} - i \frac{71}{10}

0 = 7 x^{2} - 2 x - 1

a, a^{2} + 2 ab - b^{2} = 0

t^{2} - 4.5 t + 3.5 = 0

6 x^{2} + 3 x = 0

3 p (2 p + 5) = 0

What are the solutions to the equation 5a^2-3a+6=2 ?
The solutions to the equation 5a^2-3a+6=2 are a= 3/10+i(sqrt(71))/(10),a= 3/10-i(sqrt(71))/(10)
Find the zeros of 5a^2-3a+6=2
The zeros of 5a^2-3a+6=2 are a= 3/10+i(sqrt(71))/(10),a= 3/10-i(sqrt(71))/(10)