What are the solutions to the equation solvefor a,a^2+2ab-b^2=0 ?

The solutions to the equation solvefor a,a^2+2ab-b^2=0 are a=(sqrt(2)-1)b,a=-(1+sqrt(2))b

Find the zeros of solvefor a,a^2+2ab-b^2=0

The zeros of solvefor a,a^2+2ab-b^2=0 are a=(sqrt(2)-1)b,a=-(1+sqrt(2))b

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solve for

a, a^{2} + 2 ab - b^{2} = 0

a = (2 - 1) b, a = - (1 + 2) b

Solution steps

a^{2} + 2 ab - b^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} + 2 ba - b^{2} = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 b \pm ( 2 b ) ^{2} - 4 \cdot 1 \cdot ( - b ^{2} )}{2 \cdot 1}

Simplify

(2 b)^{2} - 4 \cdot 1 \cdot (- b^{2}) : 22 b

a_{1, 2} = \frac{- 2 b \pm 2 2 b}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 2 b + 2 2 b}{2 \cdot 1}, a_{2} = \frac{- 2 b - 2 2 b}{2 \cdot 1}

a = \frac{- 2 b + 2 2 b}{2 \cdot 1} : (2 - 1) b

a = \frac{- 2 b - 2 2 b}{2 \cdot 1} : - (1 + 2) b

The solutions to the quadratic equation are:

a = (2 - 1) b, a = - (1 + 2) b

t^{2} - 4.5 t + 3.5 = 0

6 x^{2} + 3 x = 0

3 p (2 p + 5) = 0

x^{2} + 2 b x = a^{2} - b^{2}

5 x^{2} + 6 x - 34 = 0

What are the solutions to the equation solvefor a,a^2+2ab-b^2=0 ?
The solutions to the equation solvefor a,a^2+2ab-b^2=0 are a=(sqrt(2)-1)b,a=-(1+sqrt(2))b
Find the zeros of solvefor a,a^2+2ab-b^2=0
The zeros of solvefor a,a^2+2ab-b^2=0 are a=(sqrt(2)-1)b,a=-(1+sqrt(2))b