What are the solutions to the equation t^2-4.5t+3.5=0 ?

The solutions to the equation t^2-4.5t+3.5=0 are t= 7/2 ,t=1

Find the zeros of t^2-4.5t+3.5=0

The zeros of t^2-4.5t+3.5=0 are t= 7/2 ,t=1

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t^{2} - 4.5 t + 3.5 = 0

t = \frac{7}{2}, t = 1

Decimal Notation

t = 3.5, t = 1

Solution steps

t^{2} - 4.5 t + 3.5 = 0

Multiply both sides by

10

10 t^{2} - 45 t + 35 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 45 ) \pm ( - 45 ) ^{2} - 4 \cdot 10 \cdot 35}{2 \cdot 10}

(- 45)^{2} - 4 \cdot 10 \cdot 35 = 25

t_{1, 2} = \frac{- ( - 45 ) \pm 25}{2 \cdot 10}

Separate the solutions

t_{1} = \frac{- ( - 45 ) + 25}{2 \cdot 10}, t_{2} = \frac{- ( - 45 ) - 25}{2 \cdot 10}

t = \frac{- ( - 45 ) + 25}{2 \cdot 10} : \frac{7}{2}

t = \frac{- ( - 45 ) - 25}{2 \cdot 10} : 1

The solutions to the quadratic equation are:

t = \frac{7}{2}, t = 1

6 x^{2} + 3 x = 0

3 p (2 p + 5) = 0

x^{2} + 2 b x = a^{2} - b^{2}

5 x^{2} + 6 x - 34 = 0

4 x^{2} + 4 x = 7

What are the solutions to the equation t^2-4.5t+3.5=0 ?
The solutions to the equation t^2-4.5t+3.5=0 are t= 7/2 ,t=1
Find the zeros of t^2-4.5t+3.5=0
The zeros of t^2-4.5t+3.5=0 are t= 7/2 ,t=1