What are the solutions to the equation x^2+2=-4x ?

The solutions to the equation x^2+2=-4x are x=-2+sqrt(2),x=-2-sqrt(2)

Find the zeros of x^2+2=-4x

The zeros of x^2+2=-4x are x=-2+sqrt(2),x=-2-sqrt(2)

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x^{2} + 2 = - 4 x

x = - 2 + 2, x = - 2 - 2

Decimal Notation

x = - 0.58578 \dots, x = - 3.41421 \dots

Solution steps

x^{2} + 2 = - 4 x

Move

4 x

to the left side

x^{2} + 2 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 2 = 22

x_{1, 2} = \frac{- 4 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 2}{2 \cdot 1}

x = \frac{- 4 + 2 2}{2 \cdot 1} : - 2 + 2

x = \frac{- 4 - 2 2}{2 \cdot 1} : - 2 - 2

The solutions to the quadratic equation are:

x = - 2 + 2, x = - 2 - 2

c^{2} - 7 c + 3 = - 2 c

2^{2} + x^{2} = 1 0^{2}

x^{2} + 2 x + 30 = 0

0.15 x^{2} - 0.32 x - 3.6 = 0

12 x^{2} - 8 x = 14

What are the solutions to the equation x^2+2=-4x ?
The solutions to the equation x^2+2=-4x are x=-2+sqrt(2),x=-2-sqrt(2)
Find the zeros of x^2+2=-4x
The zeros of x^2+2=-4x are x=-2+sqrt(2),x=-2-sqrt(2)