What are the solutions to the equation 2(3k-1)^2=18 ?

The solutions to the equation 2(3k-1)^2=18 are k= 4/3 ,k=-2/3

Find the zeros of 2(3k-1)^2=18

The zeros of 2(3k-1)^2=18 are k= 4/3 ,k=-2/3

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2 (3 k - 1)^{2} = 18

k = \frac{4}{3}, k = - \frac{2}{3}

Decimal Notation

k = 1.33333 \dots, k = - 0.66666 \dots

Solution steps

2 (3 k - 1)^{2} = 18

Divide both sides by

2

(3 k - 1)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 k - 1 = 9 : k = \frac{4}{3}

Solve

3 k - 1 = - 9 : k = - \frac{2}{3}

The solutions to the quadratic equation are:

k = \frac{4}{3}, k = - \frac{2}{3}

- 3 x^{2} + 6 x = - 1

(- 2)^{3} = (- 2) x (- 2) x (- 2)

4 s^{2} + 4 s + 5 = 0

0 = - 2.7 t^{2} + 30 t + 6.5

f^{2} + 7 f + 10 = 0

What are the solutions to the equation 2(3k-1)^2=18 ?
The solutions to the equation 2(3k-1)^2=18 are k= 4/3 ,k=-2/3
Find the zeros of 2(3k-1)^2=18
The zeros of 2(3k-1)^2=18 are k= 4/3 ,k=-2/3