What are the solutions to the equation (-2)^3=(-2)x(-2)x(-2) ?

The solutions to the equation (-2)^3=(-2)x(-2)x(-2) are x=1,x=-1

Find the zeros of (-2)^3=(-2)x(-2)x(-2)

The zeros of (-2)^3=(-2)x(-2)x(-2) are x=1,x=-1

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(- 2)^{3} = (- 2) x (- 2) x (- 2)

x = 1, x = - 1

Solution steps

(- 2)^{3} = (- 2) x (- 2) x (- 2)

Switch sides

(- 2) x (- 2) x (- 2) = (- 2)^{3}

Simplify

- 8 x^{2} = - 8

Divide both sides by

- 8

\frac{- 8 x ^{2}}{- 8} = \frac{- 8}{- 8}

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

4 s^{2} + 4 s + 5 = 0

0 = - 2.7 t^{2} + 30 t + 6.5

f^{2} + 7 f + 10 = 0

(- 5)^{2} + (2)^{2} = D^{2}

3 x (x + 2) = 6 (x - 3)

What are the solutions to the equation (-2)^3=(-2)x(-2)x(-2) ?
The solutions to the equation (-2)^3=(-2)x(-2)x(-2) are x=1,x=-1
Find the zeros of (-2)^3=(-2)x(-2)x(-2)
The zeros of (-2)^3=(-2)x(-2)x(-2) are x=1,x=-1