What are the solutions to the equation 5x^2+20x+265=0 ?

The solutions to the equation 5x^2+20x+265=0 are x=-2+7i,x=-2-7i

Find the zeros of 5x^2+20x+265=0

The zeros of 5x^2+20x+265=0 are x=-2+7i,x=-2-7i

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5 x^{2} + 20 x + 265 = 0

x = - 2 + 7 i, x = - 2 - 7 i

Solution steps

5 x^{2} + 20 x + 265 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 5 \cdot 265}{2 \cdot 5}

Simplify

2 0^{2} - 4 \cdot 5 \cdot 265 : 70 i

x_{1, 2} = \frac{- 20 \pm 70 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 20 + 70 i}{2 \cdot 5}, x_{2} = \frac{- 20 - 70 i}{2 \cdot 5}

x = \frac{- 20 + 70 i}{2 \cdot 5} : - 2 + 7 i

x = \frac{- 20 - 70 i}{2 \cdot 5} : - 2 - 7 i

The solutions to the quadratic equation are:

x = - 2 + 7 i, x = - 2 - 7 i

(x + 2) x - 3 (x - 2) = (x + 1) 2 - (x - 3) x

(3 x + 5)^{2} = 1

(3 x + 5)^{2} = 7

48 - 48 x = (7 x + 1) (x - 1)

\frac{1}{3} m^{2} + 2 m = 4

What are the solutions to the equation 5x^2+20x+265=0 ?
The solutions to the equation 5x^2+20x+265=0 are x=-2+7i,x=-2-7i
Find the zeros of 5x^2+20x+265=0
The zeros of 5x^2+20x+265=0 are x=-2+7i,x=-2-7i