What are the solutions to the equation (2y+6)^2=36 ?

The solutions to the equation (2y+6)^2=36 are y=0,y=-6

Find the zeros of (2y+6)^2=36

The zeros of (2y+6)^2=36 are y=0,y=-6

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(2 y + 6)^{2} = 36

y = 0, y = - 6

Solution steps

(2 y + 6)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 y + 6 = 36 : y = 0

Solve

2 y + 6 = - 36 : y = - 6

The solutions to the quadratic equation are:

y = 0, y = - 6

16 x^{2} + 56 x + 49 = 0

5 x^{2} = 17 x + 40

6 r^{2} - 3 r - 4 = r^{2}

2 x - 0.2 x^{2} = \frac{1}{2} x

2 x^{2} = 13

What are the solutions to the equation (2y+6)^2=36 ?
The solutions to the equation (2y+6)^2=36 are y=0,y=-6
Find the zeros of (2y+6)^2=36
The zeros of (2y+6)^2=36 are y=0,y=-6