What are the solutions to the equation 16x^2+56x+49=0 ?

The solutions to the equation 16x^2+56x+49=0 are x=-7/4

Find the zeros of 16x^2+56x+49=0

The zeros of 16x^2+56x+49=0 are x=-7/4

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16 x^{2} + 56 x + 49 = 0

x = - \frac{7}{4}

Decimal Notation

x = - 1.75

Solution steps

16 x^{2} + 56 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 \cdot 16 \cdot 49}{2 \cdot 16}

5 6^{2} - 4 \cdot 16 \cdot 49 = 0

x_{1, 2} = \frac{- 56 \pm 0}{2 \cdot 16}

x = \frac{- 56}{2 \cdot 16}

\frac{- 56}{2 \cdot 16} = - \frac{7}{4}

x = - \frac{7}{4}

The solution to the quadratic equation is:

x = - \frac{7}{4}

5 x^{2} = 17 x + 40

6 r^{2} - 3 r - 4 = r^{2}

2 x - 0.2 x^{2} = \frac{1}{2} x

2 x^{2} = 13

2 x^{2} - 4 x - 1 = 0

What are the solutions to the equation 16x^2+56x+49=0 ?
The solutions to the equation 16x^2+56x+49=0 are x=-7/4
Find the zeros of 16x^2+56x+49=0
The zeros of 16x^2+56x+49=0 are x=-7/4