What are the solutions to the equation 2x-0.2x^2= 1/2 x ?

The solutions to the equation 2x-0.2x^2= 1/2 x are x=0,x= 15/2

Find the zeros of 2x-0.2x^2= 1/2 x

The zeros of 2x-0.2x^2= 1/2 x are x=0,x= 15/2

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2 x - 0.2 x^{2} = \frac{1}{2} x

x = 0, x = \frac{15}{2}

Decimal Notation

x = 0, x = 7.5

Solution steps

2 x - 0.2 x^{2} = \frac{1}{2} x

Multiply both sides by

10

20 x - 2 x^{2} = 5 x

Move

5 x

to the left side

- 2 x^{2} + 15 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1 5^{2} - 4 (- 2) \cdot 0 = 15

x_{1, 2} = \frac{- 15 \pm 15}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 15 + 15}{2 ( - 2 )}, x_{2} = \frac{- 15 - 15}{2 ( - 2 )}

x = \frac{- 15 + 15}{2 ( - 2 )} : 0

x = \frac{- 15 - 15}{2 ( - 2 )} : \frac{15}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{15}{2}

2 x^{2} = 13

2 x^{2} - 4 x - 1 = 0

(x - 13)^{2} = - \frac{1}{3}

3 y - y^{2} + 1 = 0

w (w + 3) = 154

What are the solutions to the equation 2x-0.2x^2= 1/2 x ?
The solutions to the equation 2x-0.2x^2= 1/2 x are x=0,x= 15/2
Find the zeros of 2x-0.2x^2= 1/2 x
The zeros of 2x-0.2x^2= 1/2 x are x=0,x= 15/2