What are the solutions to the equation 2x^2-4x=4 ?

The solutions to the equation 2x^2-4x=4 are x=1+sqrt(3),x=1-sqrt(3)

Find the zeros of 2x^2-4x=4

The zeros of 2x^2-4x=4 are x=1+sqrt(3),x=1-sqrt(3)

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2 x^{2} - 4 x = 4

x = 1 + 3, x = 1 - 3

Decimal Notation

x = 2.73205 \dots, x = - 0.73205 \dots

Solution steps

2 x^{2} - 4 x = 4

Move

4

to the left side

2 x^{2} - 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 4) = 43

x_{1, 2} = \frac{- ( - 4 ) \pm 4 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 3}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 4 3}{2 \cdot 2}

x = \frac{- ( - 4 ) + 4 3}{2 \cdot 2} : 1 + 3

x = \frac{- ( - 4 ) - 4 3}{2 \cdot 2} : 1 - 3

The solutions to the quadratic equation are:

x = 1 + 3, x = 1 - 3

6 x^{2} = - 24 x

0 = x^{2} - x - 30

k (k + 5) = 19

x^{2} - 3 x + 2 = x - 1

2 x^{2} - 3 x - 4 = 0

What are the solutions to the equation 2x^2-4x=4 ?
The solutions to the equation 2x^2-4x=4 are x=1+sqrt(3),x=1-sqrt(3)
Find the zeros of 2x^2-4x=4
The zeros of 2x^2-4x=4 are x=1+sqrt(3),x=1-sqrt(3)