What are the solutions to the equation k(k+5)=19 ?

The solutions to the equation k(k+5)=19 are k=(-5+sqrt(101))/2 ,k=(-5-sqrt(101))/2

Find the zeros of k(k+5)=19

The zeros of k(k+5)=19 are k=(-5+sqrt(101))/2 ,k=(-5-sqrt(101))/2

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k (k + 5) = 19

k = \frac{- 5 + 101}{2}, k = \frac{- 5 - 101}{2}

Decimal Notation

k = 2.52493 \dots, k = - 7.52493 \dots

Solution steps

k (k + 5) = 19

Expand

k (k + 5) : k^{2} + 5 k

k^{2} + 5 k = 19

Move

19

to the left side

k^{2} + 5 k - 19 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 19 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 19) = 101

k_{1, 2} = \frac{- 5 \pm 101}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 5 + 101}{2 \cdot 1}, k_{2} = \frac{- 5 - 101}{2 \cdot 1}

k = \frac{- 5 + 101}{2 \cdot 1} : \frac{- 5 + 101}{2}

k = \frac{- 5 - 101}{2 \cdot 1} : \frac{- 5 - 101}{2}

The solutions to the quadratic equation are:

k = \frac{- 5 + 101}{2}, k = \frac{- 5 - 101}{2}

x^{2} - 3 x + 2 = x - 1

2 x^{2} - 3 x - 4 = 0

x, 7 x^{2} - x = 7

g^{2} - 11 g - 42 = 0

(x - 2) (2 x + 5) = 0

What are the solutions to the equation k(k+5)=19 ?
The solutions to the equation k(k+5)=19 are k=(-5+sqrt(101))/2 ,k=(-5-sqrt(101))/2
Find the zeros of k(k+5)=19
The zeros of k(k+5)=19 are k=(-5+sqrt(101))/2 ,k=(-5-sqrt(101))/2