What are the solutions to the equation g^2-11g-42=0 ?

The solutions to the equation g^2-11g-42=0 are g=14,g=-3

Find the zeros of g^2-11g-42=0

The zeros of g^2-11g-42=0 are g=14,g=-3

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g^{2} - 11 g - 42 = 0

g = 14, g = - 3

Solution steps

g^{2} - 11 g - 42 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot ( - 42 )}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot (- 42) = 17

g_{1, 2} = \frac{- ( - 11 ) \pm 17}{2 \cdot 1}

Separate the solutions

g_{1} = \frac{- ( - 11 ) + 17}{2 \cdot 1}, g_{2} = \frac{- ( - 11 ) - 17}{2 \cdot 1}

g = \frac{- ( - 11 ) + 17}{2 \cdot 1} : 14

g = \frac{- ( - 11 ) - 17}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

g = 14, g = - 3

(x - 2) (2 x + 5) = 0

15 x^{2} + 17 x - 4 = 0

2 x^{2} - 12 x + 1

x^{2} - 24 x - 6 = 0

13 - 13 x = (4 x + 3) (x - 1)

What are the solutions to the equation g^2-11g-42=0 ?
The solutions to the equation g^2-11g-42=0 are g=14,g=-3
Find the zeros of g^2-11g-42=0
The zeros of g^2-11g-42=0 are g=14,g=-3