What are the solutions to the equation 9x^2+18x+82=0 ?

The solutions to the equation 9x^2+18x+82=0 are x=-1+i(sqrt(73))/3 ,x=-1-i(sqrt(73))/3

Find the zeros of 9x^2+18x+82=0

The zeros of 9x^2+18x+82=0 are x=-1+i(sqrt(73))/3 ,x=-1-i(sqrt(73))/3

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9 x^{2} + 18 x + 82 = 0

x = - 1 + i \frac{73}{3}, x = - 1 - i \frac{73}{3}

Solution steps

9 x^{2} + 18 x + 82 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 \cdot 82}{2 \cdot 9}

Simplify

1 8^{2} - 4 \cdot 9 \cdot 82 : 673 i

x_{1, 2} = \frac{- 18 \pm 6 73 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 18 + 6 73 i}{2 \cdot 9}, x_{2} = \frac{- 18 - 6 73 i}{2 \cdot 9}

x = \frac{- 18 + 6 73 i}{2 \cdot 9} : - 1 + i \frac{73}{3}

x = \frac{- 18 - 6 73 i}{2 \cdot 9} : - 1 - i \frac{73}{3}

The solutions to the quadratic equation are:

x = - 1 + i \frac{73}{3}, x = - 1 - i \frac{73}{3}

2.5 (x + 1)^{2} = 6 x^{2}

x^{2} - 18 - 3 x = 0

R^{2} + 7 R + 12 = 0

4 y^{2} - 9 y + 2 = 0

10 x = x^{2} - 11

What are the solutions to the equation 9x^2+18x+82=0 ?
The solutions to the equation 9x^2+18x+82=0 are x=-1+i(sqrt(73))/3 ,x=-1-i(sqrt(73))/3
Find the zeros of 9x^2+18x+82=0
The zeros of 9x^2+18x+82=0 are x=-1+i(sqrt(73))/3 ,x=-1-i(sqrt(73))/3