What are the solutions to the equation y^2-7y=0 ?

The solutions to the equation y^2-7y=0 are y=7,y=0

Find the zeros of y^2-7y=0

The zeros of y^2-7y=0 are y=7,y=0

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y^{2} - 7 y = 0

y = 7, y = 0

Solution steps

y^{2} - 7 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 0 = 7

y_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 1}, y_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 1}

y = \frac{- ( - 7 ) + 7}{2 \cdot 1} : 7

y = \frac{- ( - 7 ) - 7}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 7, y = 0

d^{2} - 5 d - 14 = 0

x^{2} - 6 x + 16

x^{2} + 6 x - 3

w^{2} - 14 w + 42 = 0

a^{2} x^{2} + a (b - c) x - b c = 0

What are the solutions to the equation y^2-7y=0 ?
The solutions to the equation y^2-7y=0 are y=7,y=0
Find the zeros of y^2-7y=0
The zeros of y^2-7y=0 are y=7,y=0