What are the solutions to the equation 5p^2+36=441 ?

The solutions to the equation 5p^2+36=441 are p=9,p=-9

Find the zeros of 5p^2+36=441

The zeros of 5p^2+36=441 are p=9,p=-9

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5 p^{2} + 36 = 441

p = 9, p = - 9

Solution steps

5 p^{2} + 36 = 441

Move

36

to the right side

5 p^{2} = 405

Divide both sides by

5

p^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = 81, p = - 81

81 = 9

- 81 = - 9

p = 9, p = - 9

(x - 2) (x - 10) = - 16

m^{2} - 6 m + 5 = 4 m^{2} - 8

w^{2} + 8 w + 7 = 0

25 x^{2} - 35 x - 30 = 0

(3 x - 2) (7 x - 1) = 0

What are the solutions to the equation 5p^2+36=441 ?
The solutions to the equation 5p^2+36=441 are p=9,p=-9
Find the zeros of 5p^2+36=441
The zeros of 5p^2+36=441 are p=9,p=-9