What are the solutions to the equation (2x-6)^2=0 ?

The solutions to the equation (2x-6)^2=0 are x=3

Find the zeros of (2x-6)^2=0

The zeros of (2x-6)^2=0 are x=3

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(2 x - 6)^{2} = 0

x = 3

Solution steps

(2 x - 6)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

2 x - 6 = 0 : x = 3

The solution to the quadratic equation is:

x = 3

0 = 6 x^{2} + x - 1

2 x^{2} - 3 x - 32 = 0

3 x^{2} = 1 + 6 x

x^{2} + 8 x - 15

3 (x + 2)^{2} - 2 (x - 1) (x + 1) = 11 x + 18

What are the solutions to the equation (2x-6)^2=0 ?
The solutions to the equation (2x-6)^2=0 are x=3
Find the zeros of (2x-6)^2=0
The zeros of (2x-6)^2=0 are x=3