What are the solutions to the equation 2.1x^2+9x=4 ?

The solutions to the equation 2.1x^2+9x=4 are x=(-45+sqrt(2865))/(21),x=-(45+sqrt(2865))/(21)

Find the zeros of 2.1x^2+9x=4

The zeros of 2.1x^2+9x=4 are x=(-45+sqrt(2865))/(21),x=-(45+sqrt(2865))/(21)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2.1 x^{2} + 9 x = 4

x = \frac{- 45 + 2865}{21}, x = - \frac{45 + 2865}{21}

Decimal Notation

x = 0.40598 \dots, x = - 4.69169 \dots

Solution steps

2.1 x^{2} + 9 x = 4

Multiply both sides by

10

21 x^{2} + 90 x = 40

Move

40

to the left side

21 x^{2} + 90 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 90 \pm 9 0 ^{2} - 4 \cdot 21 ( - 40 )}{2 \cdot 21}

9 0^{2} - 4 \cdot 21 (- 40) = 22865

x_{1, 2} = \frac{- 90 \pm 2 2865}{2 \cdot 21}

Separate the solutions

x_{1} = \frac{- 90 + 2 2865}{2 \cdot 21}, x_{2} = \frac{- 90 - 2 2865}{2 \cdot 21}

x = \frac{- 90 + 2 2865}{2 \cdot 21} : \frac{- 45 + 2865}{21}

x = \frac{- 90 - 2 2865}{2 \cdot 21} : - \frac{45 + 2865}{21}

The solutions to the quadratic equation are:

x = \frac{- 45 + 2865}{21}, x = - \frac{45 + 2865}{21}

a, a^{2} - ab - 12 b^{2} = 0

2 y^{2} + y = 0

10 x^{2} = 45 - 68 x

[f (a)]^{2} = 5 x^{2} - x + 3

4 a^{2} x^{2} + a b^{2} x + 5 = 0

What are the solutions to the equation 2.1x^2+9x=4 ?
The solutions to the equation 2.1x^2+9x=4 are x=(-45+sqrt(2865))/(21),x=-(45+sqrt(2865))/(21)
Find the zeros of 2.1x^2+9x=4
The zeros of 2.1x^2+9x=4 are x=(-45+sqrt(2865))/(21),x=-(45+sqrt(2865))/(21)